پاورپوینت کامل مخلوط هوا – بخار و تهویه مطبوع ۴۲ اسلاید در PowerPoint

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پاورپوینت کامل مخلوط هوا – بخار و تهویه مطبوع ۴۲ اسلاید در PowerPoint

اسلاید ۴: ۴Consider increasing the total pressure of an air-water vapor mixture while the temperature of the mixture is held constant. See if you can sketch the process on the P-v diagram relative to the saturation lines for the water alone given below. Assume that the water vapor is initially superheated.PvWhen the mixture pressure is increased while keeping the mixture temperature constant, the vapor partial pressure increases up to the vapor saturation pressure at the mixture temperature and condensation begins. Therefore, the partial pressure of the water vapor can never be greater than its saturation pressure corresponding to the temperature of the mixture.

اسلاید ۵: ۵DefinitionsDew Point, TdpThe dew point is the temperature at which vapor condenses or solidifies when cooled at constant pressure. Consider cooling an air-water vapor mixture while the mixture total pressure is held constant. When the mixture is cooled to a temperature equal to the saturation temperature for the water-vapor partial pressure, condensation begins.When an atmospheric air-vapor mixture is cooled at constant pressure such that the partial pressure of the water vapor is 1.491 kPa, then the dew point temperature of that mixture is 12.95oC.

اسلاید ۶: ۶Relative Humidity, Pv and Pg are shown on the following T-s diagram for the water-vapor alone.Since

اسلاید ۷: ۷Absolute humidity or specific humidity (sometimes called humidity ratio), Using the definition of the specific humidity, the relative humidity may be expressed as Volume of mixture per mass of dry air, vAfter several steps, we can show (you should try this)

اسلاید ۸: ۸So the volume of the mixture per unit mass of dry air is the specific volume of the dry air calculated at the mixture temperature and the partial pressure of the dry air.Mass of mixtureMass flow rate of dry air, Based on the volume flow rate of mixture at a given state, the mass flow rate of dry air isEnthalpy of mixture per mass dry air, h

اسلاید ۹: ۹Example 14-1 Atmospheric air at 30oC, 100 kPa, has a dew point of 21.3oC. Find the relative humidity, humidity ratio, and h of the mixture per mass of dry air.

اسلاید ۱۰: ۱۰

اسلاید ۱۱: ۱۱Example 14-2If the atmospheric air in the last example is conditioned to 20oC, 40 percent relative humidity, what mass of water is added or removed per unit mass of dry airAt 20oC, Pg = 2.339 kPa.The change in mass of water per mass of dry air is

اسلاید ۱۲: ۱۲Or, as the mixture changes from state 1 to state 2, 0.01038 kg of water vapor is condensed for each kg of dry air. Example 14-3 Atmospheric air is at 25oC, 0.1 MPa, 50 percent relative humidity. If the mixture is cooled at constant pressure to 10oC, find the amount of water removed per mass of dry air.Sketch the water-vapor states relative to the saturation lines on the following T-s diagram. TsAt 25oC, Psat = 3.170 kPa, and with = 50%

اسلاید ۱۳: ۱۳Therefore, when the mixture gets cooled to T2 = 10oC < Tdp,1, the mixture is saturated, and = 100%. Then Pv,2 = Pg,2 = 1.228 kPa. The change in mass of water per mass of dry air is

اسلاید ۱۴: ۱۴Or as the mixture changes from state 1 to state 2, 0.00228 kg of water vapor is condensed for each kg of dry air.Steady-Flow Analysis Applied to Gas-Vapor MixturesWe will review the conservation of mass and conservation of energy principles as they apply to gas-vapor mixtures in